/* Problem: Write a function that multiplies two integers
without using the multiplication (*) operator. */
#include <stdio.h>
int
multiply (int m, int n)
{
int answer;
if (n == 1)
answer = m;
else
answer = m + multiply (m, n-1);
return (answer);
}
int
main (void)
{
int a, b, c;
a = 20;
b = 10;
c = multiply (a, b);
printf("%d times %d is %d. \n", a, b, c);
return(0);
}
